For example:

var i = Try.These(
    function() { return 9 / 0; },
    function() { return 1; }
);

If we ran the sample above i would equal 1 because the first function would encounter a division by zero error. However:

var h = 0;
var i = Try.These(
    function() { return 9 / h; },
    function() { return 1 / h; }
);

i will equal undefined in this example.

With the .Net framework’s generics library we can achieve roughly the same results. We won’t be able to assign an undefined value to the result but we can play around with the default keyword. :D

public class Try
{
    public static T These(params Func[] delegates)
    {
        for (int i = 0; i <= delegates.Length - 1; i++)
        {
            try
            {
                return (T)delegates[i]();
            }
            catch
            {

            }
        }
        return default(T);
    }
}

So for example:

static void Main(string[] args)
{
    int i = 0;
    int y = Try.These(
        delegate() {
            int x = 0;
            return i / x;
        },

        delegate() {
            return ++i;
    });

    Console.Write("y is " + y.ToString());
}

Will output

y is 0